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Very strange, nothing works.
I am now testing only on Proteus.
Does the program have no correct errors?

As for the leds the microcontroller output is connected to the anode of the led and the ...

Thanks for the reply, Ttelmah.

The initial value was 500ms, but I had gone down to 5ms to do the test in MPLAB, in the MPLAB the output oscillates.

I have placed 50ms, value proposed by you, up ...

Hello friends, I'm having trouble with a code from an RF receiver.
Using the same settings for the PIC12F675 microcontroller of the original code, I inserted in the while the commands for output Led1 ...

I understood. Thank you friend.

Hello friends CCS compiler does not have the word reserve for creating classes in object-oriented programming with C ++? How can I create a class in CCS compiler?

Thank you.

I was looking for an explanation like that. I am passing a code in Arduino to the CCS compiler. I was having trouble figuring out how I could do normalization. So when driving a motor with a signal re ...

As Mr. T. say
Do NOT believe Proteus ! It's BUSTED, broke,incomplete, worthless...
Sadly there's a whole herd of folks who think Proteus is the next best thing to sliced bread...
however
it's NOT ...

As a comment I have just tried it in MPLAB 8.92, which the poster mentions, and in this the flag does set again merrily. If you put a break on the TMRIF=0 instruction, it happily arrives back there wi ...

It's entirely up to you.

However if your interrupt was something like an event you wanted to count, the quite large time it takes to get _out_ of the interrupt becomes significant. So in this case ...

When executing the interrupt while (1) processing is interrupted, even the overflow time being 131ms, ie no new interrupts occur while not executing the entire loop within the interrupt.

Actua ...

FOR (REPEAT = 0; REPEAT <2; REPEAT ++);
can only be executed once as repeat starts at 0, increments to 1 and
when it goes to 2, exits the loop.

Actually the loop count is OK. It should e ...

FOR (REPEAT = 0; REPEAT <2; REPEAT ++);
can only be executed once as repeat starts at 0, increments to 1 and
when it goes to 2, exits the loop.

Actually the loop count is OK. It should e ...

2 quick comments.

1st. FOR (REPEAT = 0; REPEAT <2; REPEAT ++);
can only be executed once as repeat starts at 0, increments to 1 and when it goes to 2, exits the loop

2nd. you should never, ...

Hello friends. I have a doubt in the execution of an interruption in the TIMER1 of the example, but that also applies to the TIMER0.
In the next program, the timer overflow is 131ms.
The doubt is: w ...

Are you running this 'for real' , or in a simulator?.
In a simulator, a delay can take ages to execute.
If 'for real', are you sure you will see/detect a 10uSec pulse every 100mSec?.

It's you ...