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PIC16F628 - DIP SWITCH

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kender

Joined: 09 Aug 2004
Posts: 768
Location: Silicon Valley

Re: PIC16F628 - DIP SWITCH

Posted: Sat Sep 23, 2006 8:45 pm

coseglio wrote:

##Urgent## SOS#SOS

Sounds like a homework.

coseglio wrote:

The while(1) loop i want is a infinite loop , but in my program execute only one and stop. I dont know wat is the problem with this.

You're calling getc() in the main loop without calling kbhit() first. It could be that your program waits forever for the input from the serial port. Also, it might help to add something like printf("heartbeat\n\r"); for debugging purposes at the very top or very bottom of the loop outside any if statements. Or to toggle an LED for the same purpose.

Guest

TEST

Posted: Sun Sep 24, 2006 7:04 am

Hi Kender. Thanks for the information.
Can tiy see now that is correct?

Code:

#include <16F628A.h>
#fuses INTRC_IO,NOWDT,PUT,BROWNOUT,NOLVP,NOMCLR
#include "usart.h"
#use delay (clock=4000000)
#use rs232(baud=9600,xmit=PIN_B2,rcv=PIN_B1)
SET_TRIS_A( 0x0F );
SET_TRIS_B( 0x0E );

unsigned char lerDip();

void main(void)
{
unsigned char saida;
unsigned char dados;
unsigned char aux = 0x00;
unsigned char mascara_a = 0xF0;
unsigned char entra;
unsigned char conf_dip;
int1 fotodiodo;
unsigned char endereco;

while(1)

{
   conf_dip = lerDip();
   aux = (conf_dip | mascara_a);
   entra = 0x00;
   entra = kbhit();


   if(entra);
   {
      dados = getc();
   }
if (dados == aux)
{
      fotodiodo = 0;
      fotodiodo = input(PIN_A0);
   }
if (fotodiodo)
      {
      saida = 0xFF;
      printf("%c",saida);
      }
else
      { saida = 0x00;
      printf("%c",saida);
         }
}
   }

unsigned char lerDip()
{
int8 a1;
int8 a2;
int8 a3;
int8 res;

res = 0x00;

res |= a1;
if (a1)

res |= (a2 << 1);
if (a2)

res |= (a3 << 2);
if (a3)

return res;
}

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