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pwm problem in pic 18f84431

 
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saniat



Joined: 14 Mar 2015
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pwm problem in pic 18f84431
PostPosted: Sun Mar 15, 2015 11:54 am     Reply with quote

hello,
I am using pic 18f84431. I got this assignment that i have to generate a PWM signal which will start after 10us. Now i understand that i will wait for 10us then set the timer to zero (as setting the timer to zero starts the signal). But i don't understand how will i implement this in C.

PWM frequency can be 5khz with 50 duty cycle.

thanks
saniat
Ttelmah



Joined: 11 Mar 2010
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PostPosted: Sun Mar 15, 2015 1:41 pm     Reply with quote

Which PWM?.
For the standard PWM's: set_timer2(0);
saniat



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PostPosted: Mon Mar 16, 2015 3:24 am     Reply with quote

this is a simple pwm using standard module. how can use the set_timer2(0) to have a 10us delay start a pwm signal?
Code:
#include <18F4431.h>                                                           
#device  adc=10                                                               
#include <math.h>                                                             
#fuses   XT,NOWDT,NOLVP                                                       
#use delay(crystal=20000000)
// this is a simple generation of PWm signal using the CCP1 modude(pin C2) using timer2 inturrupt.

void main()
{


   setup_timer_2(T2_DIV_BY_4,255,1);    // 20MHz clock, prescaler=1, resolution=4 *256=1024. formula: (20*1000)/(4*4*256)=4.88khz pwm frequency

  setup_ccp1(CCP_PWM);
 
   set_pwm1_duty(511L);// 50% duty cycle
 
 
   

}
Ttelmah



Joined: 11 Mar 2010
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PostPosted: Mon Mar 16, 2015 4:20 am     Reply with quote

delay_us(10);
set_timer2(0);

However do understand that the signal 'starts' as soon as you program the PWM. What setting the timer does is change where you are in the waveform.
saniat



Joined: 14 Mar 2015
Posts: 9

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PostPosted: Mon Mar 16, 2015 4:36 am     Reply with quote

so do i get a 10 us shift from the original signal?when i say the original signal i mean the signal without the 10us delay.

thank you
saniat
Ttelmah



Joined: 11 Mar 2010
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PostPosted: Mon Mar 16, 2015 5:03 am     Reply with quote

You get 10uSec, plus a couple of instruction times. The instructions the processor takes to load the timer. Nothing is ever 'instantaneous'....
saniat



Joined: 14 Mar 2015
Posts: 9

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PostPosted: Mon Mar 16, 2015 5:57 am     Reply with quote

so if generate a power pwm and a standard pwm (both same frequency and duty), by this way i can show a phase shift between 1 power pwm signal and a standard pwm signal. am i right?
Ttelmah



Joined: 11 Mar 2010
Posts: 19552

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PostPosted: Mon Mar 16, 2015 8:49 am     Reply with quote

Try searching the forum, rather than asking questions that have been answered before:

<http://www.ccsinfo.com/forum/viewtopic.php?t=53509>

Only a few weeks ago.
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