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Count How many times program goes into interrupt

 
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Micro_Guy



Joined: 06 Aug 2015
Posts: 10

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Count How many times program goes into interrupt
PostPosted: Wed Sep 07, 2016 3:29 am     Reply with quote

Hi guys,

I'm trying to figure out a way how to count how many times a program executes an ISR.

Here's the best I could come up with, but it's not working.

Any help/mentoring is greatly appreciated. I'm new to interrupts so I'm experimenting.

Thanks in advance!


Code:
#include <16F877A.h>
#fuses XT, NOWDT, NOPROTECT, BROWNOUT, PUT, NOLVP
#use delay(clock = 4M)

int8 Count=0;

#INT_TIMER2
void control_timer_isr() {
   output_toggle(pin_C2);
   Count++;
}

void main() {
 
setup_timer_2(T2_DIV_BY_16, 245, 5);                 
enable_interrupts(INT_TIMER2);
enable_interrupts(GLOBAL);   
   
while(1); 
}
Ttelmah



Joined: 11 Mar 2010
Posts: 19545

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PostPosted: Wed Sep 07, 2016 4:41 am     Reply with quote

What you post will work.

How are you testing this?.

The interrupt will be called just over 50* per second.

4000000/(4*246*5*16) = 50.813
Micro_Guy



Joined: 06 Aug 2015
Posts: 10

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PostPosted: Thu Sep 08, 2016 12:54 am     Reply with quote

I'm testing this by running the program in Step mode and monitoring the value of "Count".

I think something weird was going on with my compiler because the code seems to update "Count" just fine now.


Thanks for the quick reply Ttelmah!!!
Ttelmah



Joined: 11 Mar 2010
Posts: 19545

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PostPosted: Thu Sep 08, 2016 1:45 am     Reply with quote

I actually 'guessed' you might be in a debugger.
These can sometimes introduce slight 'oddities'. This is why sometimes it is better to actually do things like have the code run for a second, and then print 'count', to fully understand how things work.
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