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PrinceNai
Joined: 31 Oct 2016
Posts: 480
Location: Montenegro
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| MPLAB SIM error |
 Posted: Fri Jun 17, 2022 9:57 am |
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Hi all,
I've been toying with MPLAB SIM in MPLAB 8.92 using the code for Olympic averaging of A/D signal with 18f46k22. No matter which analog input I choose, I get this warning:
ADC-W0012: Selected channel 0 is an invalid channel. What is MPLAB trying to tell with this? Which channel would be valid?
I hardly ever use a simulator and imaginary stimulus, this is from curiosity only. |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Fri Jun 17, 2022 10:30 am |
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Post a short test program that compiles.
Post your compiler version.
Post details on how you are doing the stimulus.
Confirm that you have 18F46K22 selected in MPLAB's Configure menu. |
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PrinceNai
Joined: 31 Oct 2016
Posts: 480
Location: Montenegro
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| Posted: Fri Jun 17, 2022 10:43 am |
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main:
| Code: |
#include <main.h>
int16 MyADC = 0;
#INT_TIMER0
void TIMER0_isr(void)
{
}
// *********************************************
// olympic++ adc de-noising routine for 10 or 12 bit ADC values
// NOTE: you must have selected the desired ADC channel before calling
// reads 16x , sorts and tosses low4 && high 4 readings
// then averages the middle 8
unsigned int16 adchlx(void){ // read 16 - sort, keep middle 8 average
unsigned int8 i; unsigned int16 accum=0;
unsigned int16 s, b[16]; int1 didswap=1;
for ( i = 0 ; i < 16; i++ ) {
b[i]= read_adc(); // ADC set for 10 or 12 bits
delay_us(8);
} // end of for loop for multi sample
while(didswap){ // bubble sort
didswap=0;
for (i=0; i<15; i++){ // i 0-15
if(b[(i)]>b[(i+1)]){ // if low element greater than next -do swap
s=b[i]; // hold upper
b[i]=b[(1+i)];
b[(1+i)]=s;
didswap=1;
} // ~if
} // ~for
} // ~while
// now sort and keep middle 8 values
for (i=4; i<12; i++){ accum +=b[i]; }
return(accum>>3);
}
// *********************************************
void main()
{
setup_adc(ADC_CLOCK_INTERNAL); //
setup_adc_ports(sAN0);
set_adc_channel(0); //read from channel 0
enable_interrupts(INT_TIMER0);
enable_interrupts(GLOBAL);
while(TRUE)
{
MyADC = adchlx();
delay_cycles(1);
delay_ms(500);
}
}
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h:
| Code: |
#include <18F46K22.h>
#device ADC=10
#FUSES NOWDT //No Watch Dog Timer
#device ICD=TRUE
#use delay(internal=32000000)
#use rs232(baud=9600,parity=N,xmit=PIN_C6,rcv=PIN_C7,bits=8,stream=PORT1,errors)
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Device in MPLAB is ok, but I saw yellow circle regarding the ability to simulate this chip. As for the stimulus I tried two variants, simply setting AN0 to "high" and also some file I found on the net.
The code breaks here: b[i]= read_adc(); // ADC set for 10 or 12 bits
| Code: |
NOT CCS!!!!
# process to continuously inject 0 to 5 V on AN0 in 0.1 V increments every 1 ms
process InjectADCPin is
begin
loop
AN0 <= 0 mv;
loop
wait for 1 ms;
AN0 <= AN0 + 100 mv;
if AN0 > 5000 mv then
exit loop;
end if;
end loop;
end loop;
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The code compiles without any warning, version 5.104. MPLAB SIM throws that back. |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Fri Jun 17, 2022 11:37 am |
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I made a very small test program and got the same ADC-W0012 error.
Then I changed the PIC to 18F4620 and it didn't show that error.
So it's the yellow dot on MPLAB SIM. There isn't full support for 18F46K22.
As a work-around, I suggest you substitute a constant for the stimulus file.
ie., don't use stimulus. Example:
| Quote: | #include <18F46K22.h>
#device ADC=10
#FUSES NOWDT //No Watch Dog Timer
#device ICD=TRUE
#use delay(internal=32000000)
#use rs232(baud=9600,parity=N,xmit=PIN_C6,rcv=PIN_C7,bits=8,stream=PORT1,errors)
int16 MyADC = 0;
#define ADC_VALUE 1023 // *** FOR TESTING ***
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and
| Quote: |
unsigned int16 adchlx(void){ // read 16 - sort, keep middle 8 average
unsigned int8 i; unsigned int16 accum=0;
unsigned int16 s, b[16]; int1 didswap=1;
for ( i = 0 ; i < 16; i++ ) {
b[i]= ADC_VALUE; // *** FOR TESTING ***
delay_us(8);
} // end of for loop for multi sample
while(didswap){ // bubble sort
didswap=0;
for (i=0; i<15; i++){ // i 0-15
if(b[(i)]>b[(i+1)]){ // if low element greater than next -do swap
s=b[i]; // hold upper
b[i]=b[(1+i)];
b[(1+i)]=s;
didswap=1;
} // ~if
} // ~for
} // ~while
// now sort and keep middle 8 values
for (i=4; i<12; i++){ accum +=b[i]; }
return(accum>>3);
} |
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PrinceNai
Joined: 31 Oct 2016
Posts: 480
Location: Montenegro
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| Posted: Fri Jun 17, 2022 2:29 pm |
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Thanks a lot for the answers.
Regards,
Samo |
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