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Output_bit , nothing

 
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Jhonny



Joined: 30 Jan 2011
Posts: 16

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Output_bit , nothing
PostPosted: Fri Mar 27, 2015 8:42 am     Reply with quote
Hi!
I use this code:
Code:

#include <12F683.h>
#device ADC=16

#FUSES NOWDT                    //No Watch Dog Timer
#FUSES noPUT                      //Power Up Timer
#FUSES PROTECT                  //Code protected from reads
#FUSES NOBROWNOUT               //No brownout reset
#FUSES NOIESO                   //Internal External Switch Over mode disabled
#FUSES NOFCMEN                  //Fail-safe clock monitor disabled

#use delay(internal=4000000)

int16 i;
unsigned int16 data=0b0101010101010101;

void main()
{
   while(TRUE)
   {
      for(i=1;i<=16;++i)
      {
         output_bit(PIN_A5, shift_left(data,2,1));
         delay_ms(30); 
      }
   i=0;
   delay_ms(500);
 
   }//end while

}//end main

The output signal is continuous H level. What is wrong? (I'm going crazy ...) Confused
Ttelmah



Joined: 11 Mar 2010
Posts: 19553

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PostPosted: Fri Mar 27, 2015 9:19 am     Reply with quote
After 480mSec, it will be.

You are shifting a 1 in every time, so after 16shifts, data will contain all 1's....

Code:

void main()
{
   unsigned int16 temp;
   while(TRUE)
   {
      temp=data;
      for(i=0;i<16;++i)
      {
         output_bit(PIN_A5, shift_left(&temp,2,1));
         delay_ms(30);
      }
      delay_ms(500);
   }//end while

}//end main


This way the value to shift is reloaded every loop.

Remember also 'shift_left' requires an _address_. Note the '&'.

Last edited by Ttelmah on Fri Mar 27, 2015 11:44 am; edited 1 time in total
Jhonny



Joined: 30 Jan 2011
Posts: 16

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PostPosted: Fri Mar 27, 2015 10:13 am     Reply with quote
Okay, I begin to understand. Thank you very much, it seems to me that we have to work well. Embarassed
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