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dgg91
Joined: 14 Nov 2015 Posts: 8
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Read_adc() in two 8 bits variables for a 10 bit ADC conv |
Posted: Mon Nov 16, 2015 5:29 am |
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Im doing a 10bit adc conversion using PIC18F4550, and trying to send the data by USB to PC, so since USB admits 8bit data packets, i want to divide the value = read_adc() variable into two, the low and high bits. Problem is i don't know how to
the code i have is something like this for 2 channels
#DEVICE ADC=10
int8 out[4]
setup_adc_ports etc
.....
...
SET_ADC_CHANNEL(0)
output[0]=read_adc('i want here first 8 bits)
output[1]=read_adc('the other 2 bits')
Same for channel(1)
//usb things
I'm not sure if this is the best way to approach the problem so any help would be great, thx |
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Ttelmah
Joined: 11 Mar 2010 Posts: 19552
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Posted: Mon Nov 16, 2015 6:10 am |
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You don't read it into two byte, you just output the bytes from the int16. A lot of different ways to do this:
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#device ADC=10
//Then in the code
int16 val;
val=read_adc();
output[0]= make8(val,0); //LSB of val
output[1]=make8(val,1); //MSB of val
//This is 'CCS only' code
output[0] = val & 0xFF;
output[1] = val/256;
//Generic, and the compiler is efficient, and will realise it can do
///256 by just taking the high byte
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Or you can use a 'union' to allow you to access the bytes or the int16 at the same location in memory. This can be _very_ efficient, and again 'generic'. A search here will find this. Or you can be sneaky:
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*(int16 *)output=read_adc();
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This tells the compiler to treat the array address (remember an array's name is it's address), as if it pointed to an int16. Then to write the 16bit return from read_adc, directly into the memory pointed to by this address. This puts the LSB into output[0], and the MSB into output[1], without any further copying.
There are probably at least a dozen other ways of doing this.
The union is as efficient as 'make8', and is also generic.
Even better you could make the union access the same memory as 'output', to avoid the copying as well. However the compiler's optimiser is quite good, and should automatically do the pointer version as efficiently. |
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dgg91
Joined: 14 Nov 2015 Posts: 8
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Posted: Mon Nov 16, 2015 8:58 am |
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Thx for your help, i found a solution using make8 function as you said, but i will take into account the generic & efficient ways as well. |
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