|
|
View previous topic :: View next topic |
Author |
Message |
bliztkrieg
Joined: 23 Jul 2018 Posts: 20
|
problem measuring ac line freq |
Posted: Mon Jul 30, 2018 11:48 pm |
|
|
Code: | #include <18f252.h>
#DEVICE ADC=10
#use delay (clock=20M)
#fuses NOLVP, NOPROTECT, HS, NOWDT, NOBROWNOUT
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7)
//!#define MODBUS_TYPE MODBUS_TYPE_SLAVE
//!#define MODBUS_SERIAL_RX_BUFFER_SIZE 40
//!#define MODBUS_SERIAL_BAUD 38400
//!
//!#define MODBUS_SERIAL_INT_SOURCE MODBUS_INT_RDA
//!#define MODBUS_SERIAL_TX_PIN PIN_F3
//!#define MODBUS_SERIAL_RX_PIN PIN_F2
//!#define MODBUS_SERIAL_ENABLE_PIN PIN_C3 // Controls DE pin for RS485
//!
//!#include "modbus.c"
//!
//!#define MODBUS_ADDRESS 0x01
long temp = 0;
int1 int_flag = FALSE;
int1 edge_flag = TRUE;
int1 pulse_flag = FALSE;
static unsigned int16 counter = 0;
unsigned int16 ccp_delta = 0;
static unsigned int32 dc_counter = 0;
//!unsigned int16 freq = 0;
unsigned int8 timer_counter = 0;//, timer3_counter = 0;
static unsigned int32 dc_volts = 0;
const int reg_num = 3;
unsigned int16 hold_regs[reg_num]={0x00,0x00,0x00};
#INT_CCP1
void ccp_isr()
{
if(edge_flag)
{
counter = CCP_1;
setup_CCP1(CCP_CAPTURE_FE);
edge_flag = FALSE;
}
else
{
ccp_delta = CCP_1 - counter;
setup_CCP1(CCP_CAPTURE_RE);
edge_flag = TRUE;
pulse_flag = TRUE;
}
}
#INT_CCP2
void ccp2_isr()
{
dc_counter++;
}
#INT_TIMER3
void timer1_isr()
{
set_timer3(0);
timer_counter++;
if(timer_counter == 10) //reading counter after 1 sec
{
int_flag = TRUE;
}
}
void main()
{
static unsigned int32 dc = 0;
static unsigned int16 pulse = 0;
static unsigned int16 freq = 0;
setup_adc(ADC_CLOCK_INTERNAL);
setup_adc_ports(ALL_ANALOG);
setup_timer_1(T1_INTERNAL | T1_DIV_BY_8);
setup_timer_3(T3_INTERNAL | T3_DIV_BY_8);
//! set_timer1(65535); // T = 1/fosc/4 * prescalar * (65535 - tmr)
clear_interrupt(INT_CCP1);
setup_CCP1(CCP_CAPTURE_RE);
enable_interrupts(INT_CCP1);
clear_interrupt(INT_CCP2);
setup_CCP2(CCP_CAPTURE_DIV_16);
enable_interrupts(INT_CCP2);
clear_interrupt(INT_TIMER3);
enable_interrupts(INT_TIMER3);
enable_interrupts(GLOBAL);
//! modbus_init();
while(1)
{
set_adc_channel(0);
delay_us(100);
temp = (read_adc()*4.88)/10;
if(int_flag)
{
dc_volts = dc_counter;
dc_counter = 0;
timer_counter = 0;
int_flag = FALSE;
}
if(pulse_flag)
{
disable_interrupts(INT_CCP1);
pulse = ccp_delta;
enable_interrupts(INT_CCP1);
freq = (6250000/(pulse*2));
pulse_flag = FALSE;
}
dc = ((dc_volts*6631)/100000); delay_us(200); //6631
//! hold_regs[0] = temp;
//! hold_regs[1] = freq;
//! hold_regs[2] = dc;
//! //MODBUS CODE//
//! if(modbus_kbhit())
//! {
//! //check address against our address, 0 is broadcast
//! if((modbus_rx.address == MODBUS_ADDRESS) || modbus_rx.address == 0)
//! {
//! switch(modbus_rx.func)
//! {
//! case FUNC_READ_HOLDING_REGISTERS:
//! if(modbus_rx.data[0] || modbus_rx.data[2] || modbus_rx.data[1]>=reg_num ||
//! modbus_rx.data[3]+modbus_rx.data[1]>reg_num)
//! {
//! modbus_exception_rsp(MODBUS_ADDRESS,modbus_rx.func,ILLEGAL_DATA_ADDRESS);
//! }
//! else
//! {
//! modbus_read_holding_registers_rsp(MODBUS_ADDRESS,(modbus_rx.data[3]*2),
//! hold_regs+modbus_rx.data[1]);
//! }
//! break;
//!
//! default: //We don't support the function, so return exception
//! modbus_exception_rsp(MODBUS_ADDRESS,modbus_rx.func,ILLEGAL_FUNCTION);
//! }
//! }
//! }
//! //MODBUS CODE END//
printf("temp: %lu, freq: %lu, dc: %lu\r\n", temp, freq, dc);
}
}
|
hey all, i am trying to read ac line frequency but there is a problem when I'm varying AC volts (using a variac) the frequency that I'm reading is also changing. Same thing is happening on simulation as well. Can someone take a look at my code and tell me what i am doing wrong ? i have also attached schematic. Thanks in advance.
|
|
|
Ttelmah
Joined: 11 Mar 2010 Posts: 19552
|
|
Posted: Tue Jul 31, 2018 12:29 am |
|
|
You need to get rid of the capacitor on the input side. Use a bridge rectifier to feed the opto. Capacitors introduce lag. How this delays the opto switching point will vary with the input voltage.
Simplest circuit is:
<http://www.emergingtechs.org/p/zer.html>
Obviously adjust the resistor used based on the voltage involved. Your 10K total, suggests you are measuring a relatively low voltage, the example given, is working directly from mains.
This is surprisingly good.
A slightly better circuit is this one:
<https://www.edn.com/design/analog/4368740/Mains-driven-zero-crossing-detector-uses-only-a-few-high-voltage-parts>
Beware in all cases the operational voltage rating of the resistors involved. |
|
|
bliztkrieg
Joined: 23 Jul 2018 Posts: 20
|
|
Posted: Tue Jul 31, 2018 12:41 am |
|
|
Ttelmah wrote: | You need to get rid of the capacitor on the input side. Use a bridge rectifier to feed the opto. Capacitors introduce lag. How this delays the opto switching point will vary with the input voltage.
Simplest circuit is:
<http://www.emergingtechs.org/p/zer.html>
Obviously adjust the resistor used based on the voltage involved. Your 10K total, suggests you are measuring a relatively low voltage, the example given, is working directly from mains.
This is surprisingly good.
A slightly better circuit is this one:
<https://www.edn.com/design/analog/4368740/Mains-driven-zero-crossing-detector-uses-only-a-few-high-voltage-parts>
Beware in all cases the operational voltage rating of the resistors involved. |
Hey thanks for your response. I have got things working like they should but i have one little problem, when i cut off the AC supply the frequency should drop down to 0 right ? Well, it is not, it is showing me the last calculated value anything that i may have missed ? |
|
|
PCM programmer
Joined: 06 Sep 2003 Posts: 21708
|
|
Posted: Tue Jul 31, 2018 1:51 am |
|
|
bliztkrieg wrote: |
I have one little problem, when i cut off the AC supply the frequency
should drop down to 0 right ? Well, it is not, it is showing me the last
calculated value anything that i may have missed ? |
Read this thread:
http://www.ccsinfo.com/forum/viewtopic.php?t=56439&start=5 |
|
|
Ttelmah
Joined: 11 Mar 2010 Posts: 19552
|
|
Posted: Tue Jul 31, 2018 1:51 am |
|
|
No, it's not going to drop to zero.
The CCP doesn't trigger, so the last calculated value remains.
You need to add some sort of timeout to the loop. If 'pulse_flag' is not set in (say) twenty times round the loop, then set frequency to zero:
Code: |
int8 loopcnt=0;
//then in the loop
if(pulse_flag)
{
disable_interrupts(INT_CCP1);
pulse = ccp_delta;
enable_interrupts(INT_CCP1);
freq = (6250000/(pulse*2));
pulse_flag = FALSE;
loopcnt=0;
}
else
{
if (loopcnt>=20)
freq=0;
else
++loopcnt;
}
|
Every time pulse_flag is seen, loopcnt is set back to zero.
If it gets to 20 (the loop always takes over 100uSec), it'll set freq to zero. So >0.02 seconds without a pulse being seen. |
|
|
bliztkrieg
Joined: 23 Jul 2018 Posts: 20
|
|
Posted: Tue Jul 31, 2018 3:30 am |
|
|
Ttelmah wrote: | No, it's not going to drop to zero.
The CCP doesn't trigger, so the last calculated value remains.
You need to add some sort of timeout to the loop. If 'pulse_flag' is not set in (say) twenty times round the loop, then set frequency to zero:
Code: |
int8 loopcnt=0;
//then in the loop
if(pulse_flag)
{
disable_interrupts(INT_CCP1);
pulse = ccp_delta;
enable_interrupts(INT_CCP1);
freq = (6250000/(pulse*2));
pulse_flag = FALSE;
loopcnt=0;
}
else
{
if (loopcnt>=20)
freq=0;
else
++loopcnt;
}
|
Every time pulse_flag is seen, loopcnt is set back to zero.
If it gets to 20 (the loop always takes over 100uSec), it'll set freq to zero. So >0.02 seconds without a pulse being seen. |
Thanks it worked like a charm :D |
|
|
kx9
Joined: 05 Nov 2013 Posts: 3 Location: portland OR
|
measuring 60hz frequency |
Posted: Tue Sep 04, 2018 12:55 pm |
|
|
You might want to add a hysteresis gate and divide by 2 FF after opto. This will clean up the slow edges, filter noisy signals and will make the input signal voltage intolerant. |
|
|
|
|
You cannot post new topics in this forum You cannot reply to topics in this forum You cannot edit your posts in this forum You cannot delete your posts in this forum You cannot vote in polls in this forum
|
Powered by phpBB © 2001, 2005 phpBB Group
|