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sradhika1998
Joined: 21 Jun 2019 Posts: 12
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SSD1306 OLED menu interfacing with button and LED using PIC |
Posted: Fri Jun 21, 2019 8:32 am |
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Hello,
I have built a menu code, and this little code is part of big code. I am interfacing transistor in place of LED as shown in picture. But just for practical results i am using LED here.
Code: |
void discharging_USB() {
SSD1306_ClearDisplay();
cursor(starting_row);
SSD1306_GotoXY(starting_col, starting_row);
SSD1306_PutC("1. 5V 1A");
delay_ms(10);
start_row = starting_row;
start_row +=1;
SSD1306_GotoXY(starting_col, start_row);
SSD1306_PutC("2. 5V 2A");
delay_ms(10);
start_row +=1;
SSD1306_GotoXY(starting_col, start_row);
SSD1306_PutC("3. 5V 3A");
delay_ms(10);
start_row +=1;
SSD1306_GotoXY(starting_col, start_row);
SSD1306_PutC("4. Back");
delay_ms(100);
if(input_state(PIN_B5)==0 && m2==2){
if( row_Ind ==1 && output_low(PIN_B0) && output_low(PIN_B1) && output_low(PIN_B2))
{
output_low(PIN_B0);
output_low(PIN_B1);
output_high(PIN_B2);
button_select==1;
}
else if( row_Ind ==2 && output_low(PIN_B0) && output_low(PIN_B1) && output_low(PIN_B2) )
{
output_low(PIN_B0);
output_high(PIN_B1);
output_low(PIN_B2);
button_select==1;
}
else if( row_Ind==3 && output_low(PIN_B0) && output_low(PIN_B1) && output_low(PIN_B2) )
{
output_low(PIN_B1);
output_high(PIN_B0);
output_low(PIN_B2);
button_select ==1;
}
else
{
output_low(PIN_B0);
output_low(PIN_B1);
output_high(PIN_B2);
button_select==1;
}}
} |
In this code, I only get the output from pin b2 but not the b0 or b1 when i press 5V 1A in the menu.. or 5V 3A in the menu. In this code only else statement is executing. Here, m2 ==2 is the menu 2 here.
[img]https://postimg.cc/68js4q64[/img] |
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PCM programmer
Joined: 06 Sep 2003 Posts: 21708
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Re: SSD1306 OLED menu interfacing with button and LED using |
Posted: Fri Jun 21, 2019 8:58 am |
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sradhika1998 wrote: |
if( row_Ind ==1 && output_low(PIN_B0) && output_low(PIN_B1) && output_low(PIN_B2))
else if( row_Ind ==2 && output_low(PIN_B0) && output_low(PIN_B1) && output_low(PIN_B2) )
else if( row_Ind==3 && output_low(PIN_B0) && output_low(PIN_B1) && output_low(PIN_B2) )
[img]https://postimg.cc/68js4q64[/img] |
The output_low() function doesn't return a value. Maybe you really
want to use input_state() ? But output_low() in an if() statement will
not work. |
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sradhika1998
Joined: 21 Jun 2019 Posts: 12
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Re: SSD1306 OLED menu interfacing with button and LED using |
Posted: Fri Jun 21, 2019 10:15 am |
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PCM programmer wrote: |
The output_low() function doesn't return a value. Maybe you really
want to use input_state() ? But output_low() in an if() statement will
not work. |
hello I made some changes in it,
Code: |
if( row_Ind ==1 && input_state(PIN_B0)==0 && input_state(PIN_B1)==0 && input_state(PIN_B2)==0 && input_state(PIN_B5)==0 && m2==1)
{
input_state(PIN_B0)==0;
input_state(PIN_B1)==0;
input_state(PIN_B2)==1;
button_select==1;
}
else if(row_Ind ==1 && input_state(PIN_B0)==0 && input_state(PIN_B1)==0 && input_state(PIN_B2)==0 && input_state(PIN_B5)==0 && m2==1)
{ input_state(PIN_B0)==1;
input_state(PIN_B1)==0;
input_state(PIN_B2)==0;
button_select==1;}
else if (row_Ind ==1 && input_state(PIN_B0)==0 && input_state(PIN_B1)==0 && input_state(PIN_B2)==0 && input_state(PIN_B5)==0 && m2==1)
{input_state(PIN_B0)==1;
input_state(PIN_B1)==0;
input_state(PIN_B2)==0;
button_select==1;
}
else
{
input_state(PIN_B0)==0;
input_state(PIN_B1)==0;
input_state(PIN_B2)==1;
button_select==1;}
} |
But now no LED is glowing in the output. What to do? |
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PCM programmer
Joined: 06 Sep 2003 Posts: 21708
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Posted: Fri Jun 21, 2019 10:36 am |
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Quote: | input_state(PIN_B0)==0;
input_state(PIN_B1)==0;
input_state(PIN_B2)==1;
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This code won't do anything. Look at this:
Quote: | ....................
.................... input_state(PIN_B2)==1;
....................
.................... |
It compiles to nothing.
You need to learn C. |
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Ttelmah
Joined: 11 Mar 2010 Posts: 19542
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Posted: Fri Jun 21, 2019 10:44 am |
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You really need to think/explain what you are actually trying to do?.
output_low(PIN_xx);
sets an output pin low.
If a pin is being used as an output, it can't at the same time be an input.
input_state returns true/false depending on the voltage present on a pin.
If you are using a pin as an input, you can hardly drive it low a moment
later (actually there are circumstances where you can mix I/O
operations, but only by using specific timings).
How are you 'pressing' things in the menu?. Keys?. If so which pins
are these connected to, and how are they connected. If these are B0, B1
& B2, then you can hardly use these same pins to drive LED's. |
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sradhika1998
Joined: 21 Jun 2019 Posts: 12
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Posted: Sat Jun 22, 2019 2:50 am |
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Ttelmah wrote: | You really need to think/explain what you are actually trying to do?.
output_low(PIN_xx);
sets an output pin low.
If a pin is being used as an output, it can't at the same time be an input.
input_state returns true/false depending on the voltage present on a pin.
If you are using a pin as an input, you can hardly drive it low a moment
later (actually there are circumstances where you can mix I/O
operations, but only by using specific timings).
How are you 'pressing' things in the menu?. Keys?. If so which pins
are these connected to, and how are they connected. If these are B0, B1
& B2, then you can hardly use these same pins to drive LED's. |
Hello, I am switching ON the LED by using push button which then select the desired menu on OLED SSD1306
There are three button, up down and select which is connected to b5, b6, b7 pin and I want output at bo, b1, b2. Please look to the image added in main text. Now how do I switch ON the led when I select desired menu on OLED and that time other 2 led is off. |
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PCM programmer
Joined: 06 Sep 2003 Posts: 21708
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Posted: Sat Jun 22, 2019 3:08 am |
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Your buttons are connected incorrectly. Do it like this for each switch:
Code: |
+5v
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<
> 4.7K
< ___ Push button switch
To | _|_|_
PIC -----------------o o------
pin |
--- GND
-
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Then test for a logic '0' to see if a switch is pressed.
The 'off' state for each switch is a logic '1'. |
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sradhika1998
Joined: 21 Jun 2019 Posts: 12
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Posted: Sat Jun 22, 2019 4:07 am |
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PCM programmer wrote: | Your buttons are connected incorrectly. Do it like this for each switch:
Code: |
+5v
|
<
> 4.7K
< ___ Push button switch
To | _|_|_
PIC -----------------o o------
pin |
--- GND
-
|
Then test for a logic '0' to see if a switch is pressed.
The 'off' state for each switch is a logic '1'. |
Hello I have used this circuit, but the thing is it only activate b2, i guess it only works for else statement but not if. What changes I need to do so that if statement work too. |
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temtronic
Joined: 01 Jul 2010 Posts: 9244 Location: Greensville,Ontario
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Posted: Sat Jun 22, 2019 4:16 am |
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You should add a small cap across the switch. I use .68 mfd as I have a reel of them,probably 4500+ left on it. .1 mfd, .22 mfd, .05mfd make work as well.
The cap will reduce if not eliminate 'contact bounce' which is the term for multiple 'one-zero' transitions when you press and release the pushbutton.
Jay |
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sradhika1998
Joined: 21 Jun 2019 Posts: 12
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Posted: Sat Jun 22, 2019 8:09 am |
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temtronic wrote: | You should add a small cap across the switch. I use .68 mfd as I have a reel of them,probably 4500+ left on it. .1 mfd, .22 mfd, .05mfd make work as well.
The cap will reduce if not eliminate 'contact bounce' which is the term for multiple 'one-zero' transitions when you press and release the pushbutton.
Jay |
Hello, Now I have used case statement, its still not glowing any led. Please guide.
Code: |
void discharging_USB() {
SSD1306_ClearDisplay();
cursor(starting_row);
SSD1306_GotoXY(starting_col, starting_row);
SSD1306_PutC("1. 5V 1A");
delay_ms(10);
start_row = starting_row;
start_row +=1;
SSD1306_GotoXY(starting_col, start_row);
SSD1306_PutC("2. 5V 2A");
delay_ms(10);
start_row +=1;
SSD1306_GotoXY(starting_col, start_row);
SSD1306_PutC("3. 5V 3A");
delay_ms(10);
start_row +=1;
SSD1306_GotoXY(starting_col, start_row);
SSD1306_PutC("4. Back");
delay_ms(100);
if (m2==1 && row_Ind == 1 && button_select==0){
if( m2==2)
{
switch (row_Ind)
{
case 1:
output_low(PIN_B0)==0;
output_low(PIN_B1)==0;
output_high(PIN_B2)==1;
button_select==1;
break;
case 2:
output_high(PIN_B0)==0;
output_low(PIN_B1)==1;
output_low(PIN_B2)==0;
button_select==1;
break;
case 3:
output_high(PIN_B0)==1;
output_low(PIN_B1)==0;
output_low(PIN_B2)==0;
button_select==1;
break;
default:
output_low(PIN_B0)==0;
output_low(PIN_B1)==0;
output_high(PIN_B2)==1;
button_select==1;
break;
}
}
}
} |
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alan
Joined: 12 Nov 2012 Posts: 357 Location: South Africa
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Posted: Sat Jun 22, 2019 8:21 am |
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How do you expect it will ever enter the case statement.
Quote: | if (m2==1 && row_Ind == 1 && button_select==0){
if( m2==2) |
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sradhika1998
Joined: 21 Jun 2019 Posts: 12
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Posted: Sat Jun 22, 2019 8:30 am |
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alan wrote: | How do you expect it will ever enter the case statement.
Quote: | if (m2==1 && row_Ind == 1 && button_select==0){
if( m2==2) |
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I don't know how do I frame this loop.
m2==1 mean that there is menu which is considered as m2==1
for eg:
1. ABC
2. DEF
3. GHI
and when m2==2 mean that when we go to sub menu of 1. ABC 2. DEF 3. GHI
and I wanna select sub menu of ABC, which is
1. 5V 1A
2. 5V 2A
3. 5V 3A
4. Back
If I just go with m2==2 then program get confuse with which menu it will go with, either ABC, DEF or GHI
Guide me what syntax do I use in it..
Awaiting your response. |
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PCM programmer
Joined: 06 Sep 2003 Posts: 21708
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Posted: Sat Jun 22, 2019 12:25 pm |
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Stop doing this:
Quote: |
output_low(PIN_B0)==0;
output_low(PIN_B1)==0;
output_high(PIN_B2)==1;
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There is no equality test on output_high() or output_low().
Do it like this:
Code: | output_low(PIN_B0);
output_low(PIN_B1);
output_high(PIN_B2); |
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sradhika1998
Joined: 21 Jun 2019 Posts: 12
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Posted: Sat Jun 22, 2019 10:29 pm |
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PCM programmer wrote: | Stop doing this:
Quote: |
output_low(PIN_B0)==0;
output_low(PIN_B1)==0;
output_high(PIN_B2)==1;
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There is no equality test on output_high() or output_low().
Do it like this:
Code: | output_low(PIN_B0);
output_low(PIN_B1);
output_high(PIN_B2); |
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Okay, I did. And what logic should I use for switch statement? |
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Mike Walne
Joined: 19 Feb 2004 Posts: 1785 Location: Boston Spa UK
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Posted: Sun Jun 23, 2019 11:00 am |
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Quote: | If I just go with m2==2 then program get confuse with which menu it will go with, either ABC, DEF or GHI
Guide me what syntax do I use in it..
Awaiting your response. |
You are the one confused, not the program.
I'm also confused, and can't figure out what you are trying to do or how you are trying to achieve it.
This is a help you forum NOT a do it for you one.
To help us:-
Explain clearly what you are trying to do.
Provide a current diagram or list of relevant connections.
Supply SHORT complete compilable code which shows your problem.
I.e. so that we can copy and paste to test it.
You appear to be struggling with a switch/LED menu loop.
That's all you need to include.
Leave out ALL other code, and I mean remove it, don't just comment it out.
It will then be much easier for us all to help you.
Mike |
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