i have a timer0 calculate Q?

[john.whung]

#if defined(__PCM__)
#include <16F877.h>
#fuses HS,NOWDT,NOPROTECT,NOLVP
#use delay(clock=20000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7) // Jumpers: 8 to 11, 7 to 12

#elif defined(__PCH__)
#include <18F452.h>
#fuses HS,NOWDT,NOPROTECT,NOLVP
#use delay(clock=20000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7) // Jumpers: 8 to 11, 7 to 12
#endif

#define INTS_PER_SECOND 76 // (20000000/(4*256*256))

BYTE seconds; // A running seconds counter
BYTE int_count; // Number of interrupts left before a second has elapsed


#int_rtcc // This function is called every time
void clock_isr() { // the RTCC (timer0) overflows (255->0).
// For this program this is apx 76 times
if(--int_count==0) { // per second.
++seconds;
int_count=INTS_PER_SECOND;
}

}


void main() {

BYTE start;

int_count=INTS_PER_SECOND;
set_timer0(0);
setup_counters( RTCC_INTERNAL, RTCC_DIV_256 | RTCC_8_BIT);
enable_interrupts(INT_RTCC);
enable_interrupts(GLOBAL);

do {

printf("Press any key to begin.\n\r");
getc();
start=seconds;
printf("Press any key to stop.\n\r");
getc();
printf("%u seconds.\n\r",seconds-start);

} while (TRUE);

}






this code is a compiler's example.

What does it mean this expression: set_timer0(0); ?


Thanks

[sjbaxter]

It means exactly what is says .... set timer0 to a value of zero !!!

Try reading the CCS C Compiler help manual.
_________________
Regards,
Simon.

[pin62426]

setup_counters( RTCC_INTERNAL, RTCC_DIV_256 | RTCC_8_BIT);


THE code
setup_counters( RTCC_INTERNAL, RTCC_DIV_256 | RTCC_8_BIT);

What does it mean this expression ?
specifically, the "RTCC_DIV_256 | RTCC_8_BIT" mean?
how can i application code equation?

[Humberto]